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A billiard ball is a small, hard ball used in cue sports, such as carom billiards, pool, and snooker. The number, type, diameter, color, and pattern of the balls differ depending upon the specific game being played. Various particular ball properties such as hardness, friction coefficient and resilience are very important to the finer points of gameplay. From Wikipedia under the
GNU Free Documentation License a collision occurs between three moving billiard balls such that no net external force acts on the three ball ? Q. a collision occurs between three moving billiard balls such that no net external force acts on the three ball system. is the momentum of each ball conserved during the collision. and why? Asked by mr.t - Tue Oct 28 17:40:05 2008 - - 2 Answers - 0 Comments A. No, the sum of the 3 balls' momenta is constant, but each ball's momentum can change. The only claim made by conservation of momentum is that with no external forces the total system momentum remains the same. Answered by kirchwey - Tue Oct 28 18:00:52 2008 A smooth billiard ball is projected with speed u, prove that e1 Q. A smooth billiard ball is projected with speed u from A, the corner of a rectangular table ABCD so as to strike first the side of BC, then the side CD, and then return to the point A. The angle that its initial direction of motion makes with AB is @ (can't type alpha here). Show that this is impossible unless e1 A. Okay, this is going to be difficult to show here. A___B ..|.\..@...| ..|...\...| ..|...\...| ..|...\...| ..|...\...| ..|...\...| ..|...\...| ..|...\...| ..|...\...| ..|...\...| ..|...\...| ..|...\...\.| ..|...\.../| z1 ..|...\.../.| ..|...\.../..| D___\_/__C ... z2 I hope you get the picture. In elastic collisions the incoming angle of impact is equal to the outgoing angle of impact. However, this is not the case here. At z1 the incoming angle of impact is @ (by similar triangles) and the outgoing angle is &. ...\ @\ ---\ &./ .../ at z2 the angles of impact are % and $ \$ | %/ .\..|.../ ..\.|./ ...\|/ Using similar triangles, we can determine the following: [A:B] means the length of AB tan@ = [B:z1]/[A:B] tan& = [z1:C]/[C:z2] tan$ =… [cont.] Answered by Jenelle - Fri Jun 8 13:17:02 2007 billiard ball problem?
Q. a billiard ball initially at rest is given a sharp impulse by a cue. the cue is held a distance h above the centerline. the ball leaves the cue with a speed v0 and, because of its 'forward english', eventually acquires a final speed of (9/7)v0. show that: h = 4/5 r, where r is the radius of the ball. Asked by Bhaskar - Tue Nov 11 05:45:04 2008 - - 1 Answers - 0 Comments A. Take a line on the billiard table, passing through the lowest point of the ball. Let this line be AB. All the forces on the ball pass through the ball's lowest point and hence through AB. Therefore torques of all forces about AB = 0 Therefore angular momentum about AB is conserved. Initial linear speed = v0 The point where impulse is applied is at height r+h above AB. Therefore, initial angular momentum of the ball about AB = m v0 (r + h)---(1) Final linear speed = (9/7)v0 Finally the ball rolls without skidding. In that case, angular speed = linear speed/radius Therefore, final angular speed w = (9/7)v0/r Moment of inertia of the ball about AB is I = 2/5 mr^2 + mr^2 = 7/5 mr^2 Therefore total final angular momentum of the ball about… [cont.] Answered by Somu - Tue Nov 11 08:01:33 2008 From Yahoo Answer Search: "Billiard ball" Under The Hood With Duncan Williams - GE Hitachi's PRISM Reactor
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